Answers IQ test

Question 25

image/svg+xml 4 8 32 192 ?
What is the next number in this sequence?

Explanation

You can find the second number in the sequence by applying the following transformation to the first number: *2 You find the third number in the sequence by applying the following transformation to the second number: *4 You can see that this is not the same number. Every step the number in the transformation changes with +2
image/svg+xml 4 8 32 192 ? *2 *4 *6 *8 +2 +2 +2

Question statistics

Overview
Question ID: oWzv8N7i
Main category: Numerical Reasoning
Sub category: Number sequences
Difficulty Level: 11What is item difficulty?
Nr of times answered: 3169
Average IQ of people who answered this question: 105.06
Percentage of answers correct: 58.60%
Item Response Theory (IRT)What is Item Response Theory?
Item difficulty: 11 / 20What is item difficulty?
Discrimination: 1.53 What is item discrimination?
Point of Maximum Information: 102.22 What is Point of Maximum Information?
Item Characteristic Curve (ICC)
This Item Characteristic Curve shows the probability that a person with a given IQ level will correctly answer this question. This graph is based on the answers and the IQ levels of 3169 individual test takers who have answered this question.
Distractor AnalysisWhat is distractor analysis?
Average IQ of people who gave the correct answer: 107.00 Why does the average IQ of people who answer the questions differ per question?
Average IQ of people who gave an incorrect answer: 102.27
Response Time AnalysisWhat is response time analysis?
Optimal time to spend on question: 54 seconds What is the optimal response time?
Optimal time to spend on question
The graph illustrates the last 250 correct and incorrect answers to this question, as well as the time it took for test takers to arrive at the answer. Using this data, an average optimal time for answering the question is calculated. However, it should be noted that the optimal time may vary for individual test takers.

Time spent: you used 44 seconds to answer this question